question about rpmdsCompare()
David Peterson
petersod at us.ibm.com
Mon Feb 21 19:12:18 UTC 2011
I have some code that uses rpmdsCompare as follows:
rpmds x, y, z;
// code that initializes x, y, and z goes here
int result0 = rpmdsCompare(x, z);
int result1 = rpmdsCompare(y, z);
Adding printf() calls immediately before the calls to rpmdsCompare()
shows that x, y, and z contain the following information:
contents of x
-------------
type: Provides
name: kernel
epoch/version/release: 2.6.18
flags: 0x08
contents of y
-------------
type: Provides
name: kernel
epoch/version/release: 2.6.18-164.el5
flags: 0x08
contents of z
-------------
type: Requires
name: kernel
epoch/version/release: 2.6.18-238.1.1.0.1.el5
flags: 0x08
result0 gets a value of 1, indicating a match. result1 gets a
value of 0, indicating no match. Is this the expected behavior? I
would have expected a result of "no match" in both cases since
neither x nor y has an epoch/version/release value that matches z
exactly.
Thanks,
Dave
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